subreddit:

/r/mathmemes

1.2k

## my knowledge is discontinuous

Calculus(v.redd.it)
[media]

sorted by: best

143 points

2 months ago

143 points

Me, a Chemist, spamming l'chattlier's principal into everything (turns out most systems resist change)

44 points

2 months ago

44 points

Change is bad, unless it leads to a lower energy state then change me all you want!

14 points

2 months ago

14 points

Become the lowest energy state... sadly, entropy doesn't like it sometimes...

4 points

2 months ago

4 points

Sounds like you'd like depression

64 points

2 months ago

64 points

Just multiply the limit by 0/0 ( = 1)

22 points

2 months ago

Ordinal

22 points

in the format of the “cover yourself in oil” meme

0/0 can’t be done because dividing by 0 is bad

1. Call 0 to be a limit as x->infinity of 1/x
2. (1/infinity)/(1/infinity) rearranges to infinity/infinity
3. Call infinity to be limit as x->infinity of x
4. x/x=1
5. Spread chaos across the land as you solve every quandary known to man by beating it to death with Lhospital’s rule
6. Start a war among the entire human population by proving the existence of god with Lhospital’s rule

https://red.metaversum.wtf/cst2tetwn7qa1.jpeg?width=480&format=pjpg&auto=webp&v=enabled&s=4ae0cdf757d80817de7e0c1410927d07f446d2b1

20 points

2 months ago

20 points

lim x->inf x = lim x->inf x/1 = lim x->inf (dx/dx)/(d1/dx) = lim x->inf 1/0 = lim x->inf inf = infinity

*drops mic*

14 points

2 months ago*

14 points

[deleted]

6 points

2 months ago

6 points

-inf/-inf = inf/inf, but I'm assuming you mean -inf/inf.

2 points

2 months ago

Complex

2 points

I always do some factoring out for limits to infinity. Have some polynomials in the numerator and denominator? Factor out the highest power.

3 points

2 months ago

3 points

3/5 ? Lets go L'Oreal,\ look NOW it's 0/0,\ so it must've been 1 all along

2 points

2 months ago

2 points

Once I was giving an exercise session on limits. I had to make an exam for the students so I gave what I thought was a very easy question, I asked the limit as x->1 of (x+2)/(x+3). Not a single person got it right, all of them got 1 using l'hôpital's rule :).

1 points

2 months ago

1 points

Oh, think your so smart with lhopitals rule. Calculate

lim (x->0) of log(x)*exp(-x^2)/exp(-(x+sin(x))^4)

You might need to apply the rule several times.